Question

Find a point on the line through A (5,-4) and B (-2,2) that is twice as far from A as from B. |​

Answer 1

Answer:

Step-by-step explanation:

Let the required point be P(x,y).

Then, AP = 2PB

AP/PB = 2/1

or AP:PB = 2:1

Therefore x = [2×(-3)+1×5/2+1] = -1/3 and y = [2×2+1×(-4)/2+1] = 0

So, the required point is (-1/3,0)