Question

find a point on the x axis which is equidistant from - 5, - 2 and 3, 2.plzzz solve it.

Answer 1

0/1 = 2(m1) + (-2)m2
aftr cross multiplication
m1 + m2 = 2m1 - 2m2
m1 - 2m1 = -2m2 - m2
-m1 = -3m2
m1/m2 = 3/1
m1 : m2 = 3:1

Answer 2

-5+(-2)+(3+2)
-5-2+3+2
-7+5
-2