Find a point on the x-axis which is equidistant from point (7,6) and (-3,4).
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Let the point on X axis be P(x, 0) which is equidistant from the points A(7,6) and B(–3,4)
That means, PA = PB
Using the distance between two points formula
⇒
⇒
⇒
⇒ 20x = 60
⇒x = 3
The point on X axis which is equidistant from the points (7,6) and (–3,4) is (3,0)
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