Math, asked by abhishekchandra10, 11 months ago

find a point on the x axis which is equidistant from the points A(7,6) and B(-3,4)

Answers

Answered by jamu17

2

Answer:

let the point be p(x,y)

given that equidistance

so,

pA=pB

√(x-7)²+(y-6)²=√(x-(-3))²+(y-4)²

15=5x-y

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