Question

Find a point on the x -axis which is equidistant from the points (7,6) and (-3,4)

Answer 1

Answer:(3,0)

Step-by-step explanation:

Let the required point be A(a,0) on the x-axis.

Then by question,

(7-a)^2+(6-0)^2=(a+3)^2+(0-4)^2

Or, 49-14a+a^2+36==a^2+6a+9+16

Or, 85-14a=6a+25

Or,85-25=6a+14a

Or, 60=20a

Therefore a=3

Hence required point is A(3,0)