Question

Find a point on the x axis which is equidistant from the points A(5, -3) B (4,6)​

Answer 1

Answer:

Let the point on y-axis be (0,y).

By, Distance formula we have,

D=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

Therefore,

(4)

2

+(y−3)

2

=

(−6)

2

+(y−5)

2

16+y

2

+9−6y=36+y

2

+25−10y

25−6y=61−10y

4y=36

y=9

Hence, the required point is (0,9).