Question

Find a point on the y-axis equidistant from (-5, 2) and (9, -2).​

Answer 1

Answer:

(0,-7)

Step-by-step explanation:

to be equidistant the point should lie on perpendicular bisector of other two points....

slope of line joining (-5,2) n (9,-2) is -4/14

so slope of line perpendicular to it is 14/4 (as product of both is -1)

perpendicular bisector passes through (2,0) as it is midpoint of (-5,2) n (9,-2)

so eqn of perpendicular bisector is 14x-4y=28

put X=0 as we need point on y axis

we get y=-7

so ans is (0,-7)

hope that it will help