Find a point on the y-axis equidistant from (-5,2)and(9,-2).
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Heya User,
--> The desired point would be X[ 0 , y ]
--> Considering that A≡(-5,2) and B≡(9,-2)
======>AX = BX
==> (-5 -0)² + (2-y)² = (9-0)² + (-2-y)²
==> 25 + y² - 4y + 4 = 81 + y² + 4y + 4
==> 8y = 25 + 4 - 81 - 4 = 25 - 81 = -56
==> y = -7
Hence, the point on y-axis satisfying above condition is ( 0 , -7 )
--> The desired point would be X[ 0 , y ]
--> Considering that A≡(-5,2) and B≡(9,-2)
======>AX = BX
==> (-5 -0)² + (2-y)² = (9-0)² + (-2-y)²
==> 25 + y² - 4y + 4 = 81 + y² + 4y + 4
==> 8y = 25 + 4 - 81 - 4 = 25 - 81 = -56
==> y = -7
Hence, the point on y-axis satisfying above condition is ( 0 , -7 )
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