Question

find a point on the y - axis equildistant from (-5 ,2) and (9,-2).​

Answer 1

Solⁿ

let the point is (0,y)

according to question  

=> √{(y-2)² + (0+5)²} = √{(y+2)² + (0-9)²}

=>  (y-2)² + 25 = (y+2)² + 81             (square both side)

=>  y²+4-4y = y²+4y+4+56

=> 8y = -56

=> y = -7  

point = (0,-7).