find a point on the y axis which is equidistant from the points A 6,5 and B -4,3
Answers
Answer:
the answer is y = 5/2
Step-by-step explanation:
to find coordinates equidistant.
always take average.
y = (y1 + y2)/2
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Point A = (6,5)
Point B = (-4, 3)
Point on the y axis which is equidistant from the point A and B
→ Let the point be P.
→ Given that the point is on Y axis, hence the point would be (0 , y)
→ Also given points are equidistant
→ Hence,
Distance of PA = Distance of PB
→ First find the distance between PA by using distance formula
where x₁ = 0 , x₂ = 6 , y₁ = y, y₂ = 5
→ Substitute the datas,
→ Now find the distance of PB
where x₁ = 0, x₂ = -4, y₁ = y, y₂ = 3
→ Substituting the datas,
→ It is given that the LHS of equation 1 and 2 are equal, hence RHS must also be equal.
→ Squaring on both sides,
36 + ( 5 - y )² = 16 + ( 3 - y )²
→ Expanding the brackets and simplifying,
36 + 25 - 10y + y² = 16 + 9 - 6y + y²
→ Cancelling y² on both sides,
36 + 25 - 10y = 16 + 9 - 6y
61 - 10y = 25 - 6y
61 - 25 = -6y + 10y
36 = 4 y
y = 36/4
y = 9
→ Hence the point is ( 0, y ) = ( 0 , 9 )
→