Question

Find a point on the y axis which is equidistant from the point A ( 6,5) and B(-4,3)​

Answer 1

Step-by-step explanation:

let p(0,Y) be a point on they Y-axis then as per the question,we have

P=BP

=√(0-6) ^2 + (y-5)^2 = √(0+4) ^2 +(y-3) ^2

=√(6)^2+(y-5) ^2 =(4) ^2+(y-3) ^2

(square ing both sides)

=36+y^2-10y+25=16+y^2-6y^2-6y+9

=4y=36

=y=9

hence the point on Y-axis is (0, 9)