Find a point on the y-axis which is equidistant from the points A (7, 6) and B(-3, 4).
please asap class 10
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Given the points are A(7, 6) and B(-3, 4)
Let the point on y-axis be P(0, y)
AP = √(x2 - x1)² + (y2 - y1)²
= √(0-7)² + (y - 6)²
= √(-7)² + y² - 2 × 6 × y + 6²
= √49 + y² - 12y + 36
= √y² - 12y + 85
BP = √(x2 - x1)² + (y2 - y1)²
= √(0 - -3)² + (y - 4)²
= √3² + y² - 2 × y × 4 + 4²
= √9 + y² - 8y + 16
= √y² - 8y + 25
√y² - 12y + 85 = √y² - 12y + 25
Squaring both sides
y² - 12y + 85 = y² - 12y + 25
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