Find a point on X-axis and a point on Y-axis from which the graph of linear equation x-6y=3 will pass pls find step by step. will mark brainliest
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Answer:
A(3,0) and B(0,-1)
Step-by-step explanation:
We know that every point on x axis is of the form (a,0) and every point on y-axis is of the form (0,a).
To find point on x axis we have to put y=0 in the given equation.
So,we get,x-6(0)=3
or,x=3
Therefore A(3,0) is the point on x axis.
Now, similarly to find any point on y axis we have to put x=0 in the given equation,
0-3y=3
or,y=-1
Therefore,the point on y axis will be B(0,-1)
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