Question

Find a point on x axis which is equidistant from (6,3), (-4,2)

Answer 1

Step-by-step explanation:

let the point p (x,y) which is equal distance from A(6,3), B (-4,2).

HERE,

AP : BP = 1:1

SO

$x = \frac{ - 4 + 6}{2} \\ x = \frac{2}{2} \\ x = 1 \\ \\ y = \: \frac{2 + 3}{2} \\ y = \frac{5}{2}$

point is p (1,5/2)

Answer 2

Step-by-step explanation:

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