Question

Find a point on x axis which is equidistant from P(7,6) and Q(3,4)

Answer 1

Given points  A(7,6) and B(-3,4)Let the point be P(x,0) [we know that point on x-axis is (x,0)] So, AP=PB and AP2=PB2  ⇒(x-7)2+(0-6)2=(x+3)2+(0-4)2x2+49-14x + 36=x2+9+6x + 16
 49-9+36-16=6x+14x 
40+20=20x 
60/20=x
 ⇒x=3Hence, point on x-axis which is equidistant from the points A(7,6) and B(-3,4) is (3,0)

Answer 2

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