Math, asked by joisarjeet, 7 months ago

find a point on y-axis which is at a distance 13 from A(13, 11)​

Answers

Answered by akhileshknp91
0

Step-by-step explanation:

let the point B(0,Y) x=13, X = 0 , y= 11 ,Y= Y

DISTANCE= 13

Point A(13,11)

Distance between AB = √( X-x)^2+(Y-y)^2

13=√(0-13)^2+(Y-y)^2

13=√(-13)^2+(Y-11)^2

13=√169+(Y-11)^2

squaring both side

13^2= (√169+(Y-11)^2)^2

169=169+ ( Y-11)^2

169-169= (Y-11)^2

0= ((Y-11)^2

√0= Y-11

0=Y-11

Y=11

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