find a point on y-axis which is at a distance 13 from A(13, 11)
Answers
Answered by
0
Step-by-step explanation:
let the point B(0,Y) x=13, X = 0 , y= 11 ,Y= Y
DISTANCE= 13
Point A(13,11)
Distance between AB = √( X-x)^2+(Y-y)^2
13=√(0-13)^2+(Y-y)^2
13=√(-13)^2+(Y-11)^2
13=√169+(Y-11)^2
squaring both side
13^2= (√169+(Y-11)^2)^2
169=169+ ( Y-11)^2
169-169= (Y-11)^2
0= ((Y-11)^2
√0= Y-11
0=Y-11
Y=11
Similar questions