Question

find a point on y-axis which is equidistant from the point (-5,2) & (9,-2).​

Answer 1

Answer:

So, the point (0,y) is equidistant from (- 5, 2) and (-9 -2). i.e. their distance is equal. Applying distance formula, Therefore, the point on y axis which is equidistant from (- 5, 2) and (-9 -2) is (0,-7).

Answer 2

Answer:

point on y-axis = (0,y)

So, √[(0+5)² + (y-2)²] = √[(0-9)² + (y+2)²]

25 + y² - 4y + 4 = 36 + y² + 4y + 4

-8y = 11

y = -11/8

hence the point on the y-axis becomes (0,-11/8)