Question

find a point on y-axis which is equidistant from the point A 6, 5 and b - 43 ​

Answer 1

Step-by-step explanation:

Here is the the answer Nikhil sir.

Answer 2

Concept Introduction: Coordinate axes are the basic of Graphs.

Given:

We have been Given:

$a(6 \: \: 5) \\ b( - 4 \: \: 3)$

To Find:

We have to Find: find a point on y-axis which is equidistant from the points

Solution:

According to the problem, Let the point be P, therefore,

$ap = bp$

$\sqrt{ {(0 - 6)}^{2} + {(y - 5)}^{2} } = \sqrt{ {(0 + 4)}^{2} + {(y - 3)}^{2} } \\ 36 = 4y \\ y = 9$

therefore the points is

$p(0 \: \: 9)$

Final Answer: The point P is

$(0 \: \: 9)$

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