find a point on y axis which is equidistant from the points 5, - 2 and -3, 2 solution
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the origin is the solution of this graph
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the point on Y-axis is (0,y)
is equidistant from (5,-2) and (-3,2)
⇒√[25+(y+2)²]=√[9+(y-2)²]
⇒25+(y+2)²=9+(y-2)²
⇒25+y²+4y+4=9+y²-4y+4
⇒25-9+4-4+y²-y²+4y+4y=0
⇒16=-8y
⇒y=16/-8
⇒y=-2
∴Point on y axis is (0,-2)
is equidistant from (5,-2) and (-3,2)
⇒√[25+(y+2)²]=√[9+(y-2)²]
⇒25+(y+2)²=9+(y-2)²
⇒25+y²+4y+4=9+y²-4y+4
⇒25-9+4-4+y²-y²+4y+4y=0
⇒16=-8y
⇒y=16/-8
⇒y=-2
∴Point on y axis is (0,-2)
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