Find a point on y – axis which is equidistant from the points (5, -2) and (-3, 2)
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Answer:
Correct answer is
Y=0,-2
Step-by-step explanation:
Given
(5-2) , (-3,2)
Let
(5-2) be A
and
(-3,2) be B
YA=YB
YA=√(0-5)^2+(Y-2)^2
YB=√(0+3)^2+(y-2)^2
YA^2=YB^2
25+y^2+4y+4=0
9+y^2-4y+4
16=-8y
Y= -2
Hope it helps you my friend
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