Question

find a point which is equidistant from A( -5, 4) and B(-1,6)​

Answer 1

Step-by-step explanation:

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Let the required point be p(X, y) and let the given points be A(–5,4) and B(–1,6).

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PA = PB

PA² = PB²

(–5–X) ² +(4–Y)² =( –1–X)²+(6–y) ²

(25+x²+10x) + (16+y²–8y) = (1+x²+2x) +(36+y²–12y).

x²+y²+41+10x–8y = x²+y²+37+2x–12y.

x²+y²+41+10x–8y–x²–y²–37–2x+12y = 0.

4+8x+4y = 0.

8x+4y = –4.

4(2x+y) = –4

2x+y = –1

y=–1–2x.

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Hope it helps you