Question

Find a point which is equidistant from the points (1, 1), (2, 3), (-2, 2).
[Ans: -1/14, 39/14)​

Answer 1

Answer:

yes ur answer matched minr

Step-by-step explanation:

Let,

point be P(x,y)

then, PA^2 + PB^2 + PC^2

(x-1)^2+(y-1)^2 = (x-2)^2+(y-3)^2 =(x+2)^2+ (y-2 )^2

on solving,

2- 2x-2y = 13-4x-6y = 8+4x-4y

on solving we get,

x= -1/14 ; y = 39/14