Question

find a polynomial function of degree 3 such that f(2)=24 and x-1,x and x+2 are factors of the polynomial

Answer 1

Answer:

f(x)= 3(x^3+ x^2-2x)

Step-by-step explanation:

we have to find polynomial of degree 3 and it's factors are x-1,x and x+2

then we can let this polynomial be

f(x) = a (x-1)(x)(x+2)

where a is constant and this polynomial function is of degree 3.

and we know that f(2)=24 now using it

f(2)=a(2-1)(2)(2+2) =24

a (1)(2)(4)=24

8a=24

then a=3 so the function is

f(x)=3(x-1)(x)(x+2)

=3(x-1)(x^2+2x)

=3(x^3 + 2x^2 -x^2- 2x)

= 3(x^3 + x^2 - 2x)

Answer 2

Answer:

$3x {}^{3 } + 3x {}^{2} - 6x \\ hope \: its \: help \: you$