find a polynomial whose sum and product of zeroes are -1/2 and -3
Answers
Answered by
2
Hey there !!!!
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If α and β are the zeroes of the quadratic polynomial p(x)
Then p(x) can be represented as
p(x) =x²-(α+β)x+αβ
α+β is the sum of roots and αβ is product of the roots.
Now,
p(x)= x²-(-1/2 )x+(-3)
p(x)=x²+x/2-3
p(x)=2x²+x-6
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Hope this helped you...............
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If α and β are the zeroes of the quadratic polynomial p(x)
Then p(x) can be represented as
p(x) =x²-(α+β)x+αβ
α+β is the sum of roots and αβ is product of the roots.
Now,
p(x)= x²-(-1/2 )x+(-3)
p(x)=x²+x/2-3
p(x)=2x²+x-6
__________________________________________________
Hope this helped you...............
Answered by
1
Hi friend!!
Let à and ß are the zeroes of the polynomial.
Sum of zeroes = -½
à + ß = -½
Product of zeroes = -3
àß = -3
A quadratic polynomial with two zeroes is in the form
k(x² - (à+ß)x + àß)
→ k(x² - (-½)x + (-3))
→ k(x² + x/2 - 3)
Put k = 2
→ 2x²+x-6
Hope it helps...
Let à and ß are the zeroes of the polynomial.
Sum of zeroes = -½
à + ß = -½
Product of zeroes = -3
àß = -3
A quadratic polynomial with two zeroes is in the form
k(x² - (à+ß)x + àß)
→ k(x² - (-½)x + (-3))
→ k(x² + x/2 - 3)
Put k = 2
→ 2x²+x-6
Hope it helps...
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