Question

find a polynomial whose zeroes are 2,1and-1.what is its degree​

Answer 1

Answer:

Step-by-step explanation:

x= 1 => x-1=0

x= -1 => x+1=0

x=2 => x-2=0

The polynomial f(x) = (x-1)(x-2)(x+1)

= (x^2-1)(x-2)

= x^3-2x^2-x+2

The degree of this polynomial is 3

Answer 2

Step-by-step explanation:

let the polynomial be ( x)

factor of p(x) are (x-2) (x-1) (x+1)

(x-2) (x^2-1)

x(x^2-1) - 2(x^2-1)

x^3-x-2x^2+2

x^3-2x^2+x+2

so, degree is 3