Question

Find a polynomial whose zeros are -1/2 and 1/3​

Answer 1

Answer:

$clearly \: let \: \alpha \: and \: \beta \: be \: he \: zeroes \: of \: p(x)\\ sum \: of \: zeroes \: = \alpha + \beta \\ \frac{ - b}{a} = \frac{ - 1}{2} + \frac{1}{3} \\ = \frac{ - 1}{6} \\ product \: of \: zeroes \: = \alpha \beta \\ \frac{c}{a} = \frac{ - 1}{2} \times \frac{1}{3} \\ = \frac{ - 1}{6} \\ hence \:t he \: required \: p(x) = {6x}^{2} - x - 1$

Answer 2

6x²-x-1 = 0

Thanks!!!!!