find a polynomial whose zeros are 2, 1 and -1 what is its degree
yadavradheshyapajtk8:
very good
Answers
Answered by
9
since it has 3 zeros given
hence its degree is either 3 or more than 3....
hence factors
(x-2)
(x-1)
(x+1)
hence polynomial
.((x-2)(x-1)(x+1)
hence its degree is either 3 or more than 3....
hence factors
(x-2)
(x-1)
(x+1)
hence polynomial
.((x-2)(x-1)(x+1)
Answered by
10
Given zeroes = 2 , 1 , -1
Number of zeroes = 3 , So it is a cubic polynomial with degree 3 .
The polynomial
= ( x - 2 ) ( x - 1 ) ( x + 1 )
= x - 2 ( x² - 1 )
= x³ - x -2x² + 2
= x³ - 2x² - x + 2 .
Therefore the polynomial is of degree 3 , and it is x³ - 2x² - x + 2 .
Number of zeroes = 3 , So it is a cubic polynomial with degree 3 .
The polynomial
= ( x - 2 ) ( x - 1 ) ( x + 1 )
= x - 2 ( x² - 1 )
= x³ - x -2x² + 2
= x³ - 2x² - x + 2 .
Therefore the polynomial is of degree 3 , and it is x³ - 2x² - x + 2 .
The degree can also be greater than 3 bro
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