Question

find a polynomial whose zeros are squares of the zeroes of the polynomial 3x square+6x-9.

Answer 1

here is u r answer

hope u understand

Answer 2

Answer:

$\text{The polynomial is }x^2-10x+9$

Step-by-step explanation:

$\text{Given the polynomial }3x^2+6x-9$

we have to find the polynomial whose zeroes are squares of the zeroes of the polynomial.

$3x^2+6x-9$

$3x^2+9x-3x-9$

$3x(x+3)-3(x+3)$

$(3x-3)(x+3)$

Hence, the zeroes are

3x-3=0 ⇒ x=1

x+3=0  ⇒ x=-3

Now, we have to find the polynomial whose zeroes are squares of the zeroes of the polynomial i.e 1 and 9

Hence, the polynomial is

$(x-1)(x-9)$

$x(x-9)-1(x-9)$

$x^2-9x-x+9$

$x^2-10x+9$

which is required polynomial.