Question

find a polynomial with zeros -2 and1÷3

Answer 1

HEY MATE!!

$\\ usually \: we \: use \: k( {x}^{2} - ( \alpha + \beta ) + \alpha \beta ) \\ \\ here \: \alpha = - 2 \: and \: \beta = 1 \div 3 \\ \\ therefore \: k( {x}^{2} - ( - 2 + 1 \div 3) \: + ( - 2)(1 \div 3)) \\ \\ k( { x}^{2} + 5 \div 3 - 2 \div 3) \\ \\ muliplying \: with \: 3 \: we \: will \: get \: \\ \\ 3 {x}^{2} + 5 - 2$
I HOPE IT HELPS YOU!!

@Be brainly