Question

find a polynomial x whose one of zeros are 3+√2

Answer 1

Step-by-step explanation:

so second zero has to be 3-√2

(irrational roots occur in pairs)

so sum of roots=-b/a=3+√2+3-√2=6

product of roots =c/a=(3-√2)(3+√2)=7

hence expression is

x²-6x+7=0 has root 3+√2