Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.
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let the number be x
60/x=x+17
60=xsquare + 17x
xsquare +17x -60
xsquare +20x-3x-60
x(x+20)-3(x+20)
(x-3)(x+20)
therefore x=3
60/x=x+17
60=xsquare + 17x
xsquare +17x -60
xsquare +20x-3x-60
x(x+20)-3(x+20)
(x-3)(x+20)
therefore x=3
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