Question

Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

Answer 1

If the number is x,

Then, x + 17 = 60/x

x2 + 17x - 60 = 0

(x + 20)(x - 3) = 0

x = 3, -20, so x = 3 (as 3 is positive)

Answer 2

Let the positive number be x.

Given that A number when increased by 17 is equal to 60 times the reciprocal of the number.

= > x + 17 = (60/x).

= > x(x + 17) = 60

= > x^2 + 17x = 60

= > x^2 + 17x - 60 = 0

= > x^2 - 3x + 20x - 60 = 0

= > x(x - 3) + 20(x - 3) = 0

= > (x - 3)(x + 20) = 0

= > x = 3, -20[Neglect negative values]

= > x = 3.

Therefore, the positive number is 3.

Hope this helps!