Question

find a positive number which when increased by 17 is equal to 60 times the reciprocal of a number​

Answer 1

Answer:

3

Step-by-step explanation:

Let the number be x

x + 17  = 60 * 1/x = 60/x

x * (x+17) = 60

x² + 17x - 60 = 0

(x+20)(x -3) = 0

x+20 = 0      or x-3 = 0

x = (-20) or x = 3

x is a positive number. so  x = 3

Answer 2

Step-by-step explanation:

Let the positive number be x, then it's reciprocal will be 1/x.

According to the question, equation formed is:

x + 17 = 60 (1/x)

x + 17 = 60/x

Taking x from RHS to LHS ,

x^2 + 17x = 60

This can be written as,

x^2 + 17x - 60 = 0

x^2 + 20x - 3x - 60 = 0

x (x + 20) - 3 (x + 20) = 0

(x - 3) (x + 20) = 0

So,

x - 3 = 0 OR x + 20 = 0

Hence, x = 3. OR. x = -20

As x is positive, x is 3.

Hence, x = 3