Question

find a Pythagoras triplets whose smallest member is 21
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Answer 1

1st equation:

2m = 21

m = 21/2

m = 10.5

2nd equation:

m²+1

(10.5)²+1

110.25+1

111.25

3rd equation:

m²-1

(10.5)²-1

110.25-1

109.25

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Answer 2

Step-by-step explanation:

For every natural number m>2,(2m,m

2

−1,m

2

+1) is a pythagorean triplet and the smallest number is 2m

Given:2m=20⇒m=

2

20

=10

⇒m

2

−1=10

2

−1=100−1=99

and m

2

+1=10

2

+1=100+1=101

∴ The triplet is (20,99,101)