find a Pythagorean triplet correes ponding n=5
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If N = 5
Then 2n = 2*5 = 10
n^2 +1 = 25+1 = 26
n^2-1 = 24
Answered by
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The Pythagorean Triplets corresponding to n=5 are
2n = 10
n^2+1 =26
n^2-1 =24
THEREFORE the triplets are 10,24,26.
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