Math, asked by cadetsukrit7718, 9 months ago

find a Pythagorean triplet correes ponding n=5​

Answers

Answered by Anonymous
0

If N = 5

Then 2n = 2*5 = 10

n^2 +1 = 25+1 = 26

n^2-1 = 24

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Answered by Anonymous
1

The Pythagorean Triplets corresponding to n=5 are

2n = 10

n^2+1 =26

n^2-1 =24

THEREFORE the triplets are 10,24,26.

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