Question

Find a Pythagorean triplet for which one number is 10
(Using the formula 2m comma and square minus one, and square + 1 )
The answer should be 6, 8, 10
Please help me

Answer 1

Answer:

6,8,10

Step-by-step explanation:

Formula = 2m , m^2 - 1 , m^2+1

m^2 + 1 = 10

m^2 = 10 - 1 = 9

m = 3

2m = 3 ×2 = 6

m^2 - 1= 9 - 1 = 8

m^2 +1 = 9+1 =10

Therefore pythagorean triplet = 6,8,10

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