find a Pythagorean triplet having 7 as largest number
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1
For any natural number greater than 1,(2m,m
2
−1,m
2
+1) is Pythagorean triplets.
So, if one number is 2m, then another two numbers will be m
2
−1 and m
2
+1.
Given, one number = 4
Then Pythagorean triplets:
2m=4 or m = 2
So,
m
2
−1=(2)
2
−1=4−1=3
m
2
+1=(2)
2
+1=4+1=5
Now, (3)
2
+(4)
2
=(5)
2
Or 9 + 16 = 25
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