Question

Find a Pythagorean triplet in which are member is 16 ​

Answer 1

We know that Pythagorean triplets are of the form 2m, m^2 −1 and m^2 + 1 .

Let us substitute 2m=16. Divide the whole expression by 2 and find the value of m. We know that the square of 8 is 64. Using this, we can find m^2 −1 and m^2 +1 .

Then ,

m = 8

m^2 - 1 = 63

m^2 + 1 = 65

Answer :

Therefore, the triplets are 16, 63 and 65.

Therefore, the triplets are 16, 63 and 65.Hence, the Pythagorean triplet whose one member is 16 is 16, 63 and 65.