find a Pythagorean triplet in which one number is 20
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Here is your answer
20,21 and 29
vikram1745:
please solve it
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to find Pythagorean triplets
2m ,m^2+1,m^2-1
now 2m =20
m=10
Second of them
m^2+1=10×10+1
=101
third one
m^2-1= 10×10-1
=99
So the triplets are 20,99,101
plz plz mark as brainliest
2m ,m^2+1,m^2-1
now 2m =20
m=10
Second of them
m^2+1=10×10+1
=101
third one
m^2-1= 10×10-1
=99
So the triplets are 20,99,101
plz plz mark as brainliest
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