Question

Find a Pythagorean triplet of 63

Answer 1

As we know 2m, m²+1, m²-1 form a Pythagorean triplet for any number, m>1

Let m= 8

2m= 2×8= 16

m²+1= 8²+1= 64+1=65

m²-1= 8²- 1= 64- 1= 63

hence the other members are 16, 65,63

Answer 2

As we know 2m, m²+1, m²-1 form a Pythagorean triplet for any number, m>1

Let m= 8

2m= 2×8= 16

m²+1= 8²+1= 64+1=65

m²-1= 8²- 1= 64- 1= 63

hence the other members are 16, 65,63