find a pythagorean triplet of which 65 is a part
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three triplets are 2n , n^2 -1 & n^2 +1
2n = 65
n = 65/2
n = 32.5
now
first triplet =65
second triplet = n^2-1
= 32.5× 32.5 -1
= 1056.25 -1
= 1055.25
third triplet = n^2 +1
=32.5 ×32.5 +1
= 1056.25 +1
= 1057.25
here is ur answer.
2n = 65
n = 65/2
n = 32.5
now
first triplet =65
second triplet = n^2-1
= 32.5× 32.5 -1
= 1056.25 -1
= 1055.25
third triplet = n^2 +1
=32.5 ×32.5 +1
= 1056.25 +1
= 1057.25
here is ur answer.
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