Question

Find a Pythagorean triplet, when n = 8​

Answer 1

Answer:

Step-by-step explanation:

Now, second number = m² -1 = 4² - 1 = 15. and, third number = m² + 1 = 4² + 1 = 17. Hence, the triplet is 8, 15 and 17. 289 = 289

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Answer 2

Answer:

48,64,80

Step-by-step explanation:

ANSWER

Condition for constructing Pythagorean triples:

When m and n are any two positive integers (m<n):

a=n

2

−m

2

b=2nm

c=n

2

+m

2

Then a,b and c are Pythagorean triple

Here m=4 and n=8

∴8

2

−4

2

⇒64−16=48

∴b=2×8×4=64

∴c=8

2

+4

2

⇒64+16=80

Hence, Pythagorean triples are 48,64,80.