Question

Find a Pythagorean triplet where one member is 5​

Answer 1

Answer:

5,12,13

Step-by-step explanation:

5²=25

25/2=12.5

12.5 lies between 12 and 13

so 5,12,13

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Answer 2

Answer:

$5,12,13$

Step-by-step explanation:

as the number 5 is odd,

the triplets are n, $(n²+1)/2, (n²-1)/2$

$= 5, (5²+1)/2, (5²-1)/2$

$= 5, 13, 12$

PROVE -

$5² +12²= 25+ 144 = 169 = 13²$