Find a Pythagorean triplet where one of the member is 16
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by formula 2 m and othe i used
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2m = 16
M=16/2=8
M^+1
8^+1=65
M^-1
8^-1=63
So, the triplets are 8,65,63
Hope it helps u
Thanks
M=16/2=8
M^+1
8^+1=65
M^-1
8^-1=63
So, the triplets are 8,65,63
Hope it helps u
Thanks
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