Question

find a Pythagorean triplet whose 1 member is​

Answer 1

Answer:

2m, m 2 − 1 , m 2 + 1 \mathrm{m}^{2}-1, \mathrm{m}^{2}+1 m2−1,m2+1 is a Pythagorean triplet. ∴ (6, 8, 10) is a Pythagorean triplet. ∴ (14, 48, 50) is not a Pythagorean triplet.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

given :

find a Pythagorean triplet whose 1 member is

to find:

1 member is

solution :

• n²-1

• 2n

• n² +1

• In our case n = 323

• substitution we have :

• n²-1= 323² -1 = 104328

• 2n = 323 x 2 = 646

• n² + 1 = 104330

• tripplet is thus :

• 104328, 646, 104330