Question

find a Pythagorean triplet whose 1 member is 6​

Answer 1

Step-by-step explanation:

Given 6 is the smallest number in Pythagorean triplet But we have for every number m>1, we have (2m, m²-1, m²+1) as a Pythagorean triplet Using the above condition we can write as 2m = 6

m=6/2=3

Then m² = 9

m² – 1 = 9 – 1 = 8

m² + 1 = 9 + 1 =10

Therefore the Pythagorean triplet is = (2m, m²-1, m²+1) = (6, 8, 10)

Answer 2

Answer:

Given 6 is the smallest number in Pythagorean triplet But we have for every number m>1, we have (2m, m²-1, m²+1) as a Pythagorean triplet Using the above condition we can write as 2m = 6

m=6/2=3

Then m² = 9

m² – 1 = 9 – 1 = 8

m² + 1 = 9 + 1 =10

Therefore the Pythagorean triplet is = (2m, m²-1, m²+1) = (6, 8, 10)

Step-by-step explanation:

PLS MARK ME AS A BRAINLIST