find a pythagorean triplet whose greater number is 29....ans= 20,21,29...
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Step-by-step explanation:
As we know ,
hypotenuse ^2 = leg^1 + leg2^2
then , 29= hypotenuse coz it is greater side
29^2 = leg1^2 +leg2^2
841 = (20)^2 + (21)^2 ( we should take any two numbers such that the sum of their square is equal to hypotenuse square)
let us check ;;;
20^2 = 400 + 21^2 = 441
400+441= 841
hence it is correct
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phythagorean triplet of three numbers where the square of greater number is equal to sum of square of other two numbers
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