Question

find a Pythagorean triplet whose one member is 10​

Answer 1

Answer:

hsq.=psq.+b sq.=h2=100+1=h=under root100=10

Step-by-step explanation:

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Answer 2

We know that, Pythagorean Triplet is in the form 2m, m² + 1 and m² - 1. But this is for any natural number m > 1

Solution :

$\bullet$Let 2m = 10

So, m = 5

$\bullet$ m² + 1

=> 5² + 1

=> 25 + 1

= 26

$\bullet$ m² - 1

=> 5² - 1

=> 25 - 1

= 24

Hence, the Pythagorean Triplet is 10, 24 and 26

Let's check it :-

10² + 24² = 26²

=> 100 + 576 = 676

=> 676 = 676

LHS = RHS

Hence, the triplet is 10, 24 and 26