Question

find a pythagorean triplet whose one member is 10 ; ans us 6 8 and 10

Answer 1

Take the square of 10 (10^2=100)

divide it by 2 (100/2=50)

i)add 2 to 50(50+2=52) ii)subtract 2 by 50(50–2=48)

divide them by 2;

i)52/2=26 ii)48/2=24

10,24,26 are the triple (10^2+24^2=26^2)

and because 3,4,5 are a triple their double must also be so 6,8,10 are also a triple(6^2+8^2=10^2)

Hope this helps you mate