Question

find a Pythagorean triplet whose one member is 15 the direct answer is 13,84,85​

Answer 1

Given :

• One member of a pythagorean triplet is 15.

To Find :

• We've to find the pythagorean triplet whose one member is 15.

Solution :

To calculate the pythagorean triplets, we will apply the below method :

$\bullet$ 2m, m² - 1 and m² + 1

Substituting values,

$\implies \tt \: 2m \\ \implies \tt \: m = \frac{\cancel{15}}{ \not2} \\ \implies \tt \: m = 7.5$

Here, value of m can't be in decimal form so,

$\implies \tt \: m^2 = 16 \\ \implies \bf \: m = 4$

So, the value of m is 4.

A.T.Q :

The pythagorean triplets are,

$\implies \tt \: 2m = 2 \times 4 \\ \implies \bf \: 8$

$\implies \tt \: {m}^{2} - 1 \\ \implies \tt 16 - 1 \\ \implies \bf \: 15$

$\implies \tt \: {m}^{2} + 1 \\ \implies \tt 16 + 1 \\ \implies \bf \: 17$

Therefore, the pythagorean triplets are 8, 15 & 17 respectively!

Answer 2

Step-by-step explanation:

Given:-

• number is 15.  

To find:

• Other Pythagorean triplet.

SoluTion:-

Pythagorean triplets are in the form of,  

2m , m² - 1 and m² + 1

Therefore,

2m = 15

⇒ m = 7.5   ( m can not be a decimal )  

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m² - 1 = 15

⇒ m² = 16  

⇒ m = ±4  

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m² + 1 = 15

⇒ m² = 14 ( No whole number for m² = 14 )

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So, we know that 'm' cannot be a decimal therefor value of m = 4

⇒ m = 4

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Now Pythagorean triplets

= 2m , m² - 1 , m² + 1

= 2(4) , 4² - 1 , 4² + 1

= 8 , 16 - 1 , 16 + 1

= 8 , 15 , 17

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